integral from 0 to 1 of |x|

Lösung

\int_{0}^{1} ∣ x ∣ d x

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{0}^{1} ∣ x ∣ d x

Entferne die Extremwerte

= \int_{0}^{1} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= \frac{1}{2}

t an g e n t f (x) = x + x, at x = 1

\int_{0}^{1} 2^{- θ} d θ

x \to 0 lim (3 x - 4)

\frac{d}{d y} (cos (x y))

\frac{d y}{d t} = \frac{t}{t ^{2} y + y}