What is the solution for (dy)/(dx)=((y^3+x^3))/(xy^2) ?

The solution for (dy)/(dx)=((y^3+x^3))/(xy^2) is y=x\sqrt[3]{3ln(x)+c_{1}}

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(dy)/(dx)=((y^3+x^3))/(xy^2)

\frac{d y}{d x} = \frac{( y ^{3} + x ^{3} )}{x y ^{2}}

y = x 3 3 ln (x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( y ^{3} + x ^{3} )}{x y ^{2}}

Solve Bernoulli ODE:

y = x 3 3 ln (x) + c_{1}

y = x 3 3 ln (x) + c_{1}

f a c t or t^{3} - 6 t^{2} + 9 t

\int_{0}^{\infty} e^{- t} d t

d er i v a t i v e \frac{1}{2 y}

a re a y = \frac{40}{x}, y = - 9 x + 39

\frac{d}{d x} (6 x - 2 x)

What is the solution for (dy)/(dx)=((y^3+x^3))/(xy^2) ?
The solution for (dy)/(dx)=((y^3+x^3))/(xy^2) is y=x\sqrt[3]{3ln(x)+c_{1}}