What is the derivative of 1/(2y) ?

The derivative of 1/(2y) is -1/(2y^2)

What is the first derivative of 1/(2y) ?

The first derivative of 1/(2y) is -1/(2y^2)

derivative of

\frac{1}{2 y}

- \frac{1}{2 y ^{2}}

Solution steps

\frac{d}{d y} (\frac{1}{2 y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot y^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot y^{- 1 - 1}) : - \frac{1}{2 y ^{2}}

= - \frac{1}{2 y ^{2}}

a re a y = \frac{40}{x}, y = - 9 x + 39

\frac{d}{d x} (6 x - 2 x)

\int_{- 5}^{6} 0

\frac{d}{d x} (- 6 sin (x) - 6 x cos (x) + x^{2} sin (x))

d er i v a t i v e y = x^{8} f (x)

What is the derivative of 1/(2y) ?
The derivative of 1/(2y) is -1/(2y^2)
What is the first derivative of 1/(2y) ?
The first derivative of 1/(2y) is -1/(2y^2)