What is the solution for (dy)/(dx)+y/x =x^3y^2 ?

The solution for (dy)/(dx)+y/x =x^3y^2 is y= 3/(x(-x^3+c_{1))}

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(dy)/(dx)+y/x =x^3y^2

\frac{d y}{d x} + \frac{y}{x} = x^{3} y^{2}

y = \frac{3}{x ( - x ^{3} + c _{1} )}

Solution steps

\frac{d y}{d x} + \frac{y}{x} = x^{3} y^{2}

Solve Bernoulli ODE:

y = \frac{3}{x ( - x ^{3} + c _{1} )}

y = \frac{3}{x ( - x ^{3} + c _{1} )}

\frac{d}{d x} (ln e^{1 + x^{2}} + 3 x^{4} + cot^{2} (π x))

(\frac{1}{1 + e ^{- x}})^{^{'}}

p a r i t y \frac{tan ( x )}{x}

\int x - x + 2 d x

\int \frac{x}{( 4 x ^{2} + 3 ) ^{6}} d x

What is the solution for (dy)/(dx)+y/x =x^3y^2 ?
The solution for (dy)/(dx)+y/x =x^3y^2 is y= 3/(x(-x^3+c_{1))}