What is the integral from 0 to infinity of u(t) ?

The integral from 0 to infinity of u(t) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to infinity of u(t)

\int_{0}^{\infty} u (t) d t

diverges

Solution steps

\int_{0}^{\infty} u t d t

Compute the indefinite integral:

\int u t d t = \frac{u t ^{2}}{2} + C

Compute the boundaries:

\int_{0}^{\infty} u (t) d t =

diverges

= diverges

x \to \infty lim (x \cdot 1)

\int t e^{- s t} d t

a re a \frac{17}{4} - \frac{1}{x}, x, \frac{1}{4}, 4

\int e^{5 x + 7} d x

\int cos^{5} (3 x) d x

What is the integral from 0 to infinity of u(t) ?
The integral from 0 to infinity of u(t) is diverges