What is the tangent of f(x)=x^2-x,\at x=-2 ?

The tangent of f(x)=x^2-x,\at x=-2 is y=-5x-4

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tangent of f(x)=x^2-x,\at x=-2

tangent of

f (x) = x^{2} - x, at x = - 2

y = - 5 x - 4

Solution steps

Find the tangent point:

(- 2, 6)

Find the slope of

f (x) = x^{2} - x : \frac{df ( x )}{d x} = 2 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(- 2, 6) : y = - 5 x - 4

y = - 5 x - 4

\int \frac{3}{5 x - 1} d x

\int (x^{2} - 7 x + 4) d x

\frac{d y}{d x} + \frac{y}{x} = e^{x}

\frac{d}{d x} (e^{2 x} + e^{- 3 x})

t an g e n t y = arccos (x) + x

What is the tangent of f(x)=x^2-x,\at x=-2 ?
The tangent of f(x)=x^2-x,\at x=-2 is y=-5x-4