What is the derivative of e^{2x}+e^{-3x} ?

The derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}

What is the first derivative of e^{2x}+e^{-3x} ?

The first derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}

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\frac{d}{d x} (e^{2 x} + e^{- 3 x})

e^{2 x} \cdot 2 - 3 e^{- 3 x}

Solution steps

\frac{d}{d x} (e^{2 x} + e^{- 3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (e^{- 3 x})

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (e^{- 3 x}) = - 3 e^{- 3 x}

= e^{2 x} \cdot 2 - 3 e^{- 3 x}

t an g e n t y = arccos (x) + x

7 x^{2} \frac{d y}{d x} = \frac{d y}{d x} + 7 x e^{- y}

t^{2} y^{^{''}} + 4 t y^{^{'}} - 18 y = 0

\frac{\partial}{\partial x} (- 2 x e^{- 3 x y})

d er i v a t i v e e^{\frac{3}{x}}

What is the derivative of e^{2x}+e^{-3x} ?
The derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}
What is the first derivative of e^{2x}+e^{-3x} ?
The first derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}