What is the solution for y^'=0.1*y-250000 ?

The solution for y^'=0.1*y-250000 is y=e^{(t+c_{1})/(10)}*10+2500000

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y^'=0.1*y-250000

y^{^{'}} = 0.1 \cdot y - 250000

y = e^{\frac{t + c _{1}}{10}} \cdot 10 + 2500000

Solution steps

y^{'} (t) = 0.1 \cdot y - 250000

Solve separable ODE:

y = e^{\frac{t + c _{1}}{10}} \cdot 10 + 2500000

y = e^{\frac{t + c _{1}}{10}} \cdot 10 + 2500000

What is the solution for y^'=0.1*y-250000 ?
The solution for y^'=0.1*y-250000 is y=e^{(t+c_{1})/(10)}*10+2500000