What is area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 ?

The answer to area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 is No Solution

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area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2

area

f (x) = \frac{x}{9 - x ^{2}}, g (y) = 0, y = 2

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

0 = 2 :

False

0 = \frac{x}{9 - x ^{2}} : x = 0

2 = \frac{x}{9 - x ^{2}} : x = \frac{6}{5}

Curves not bounded

= No Solution

\frac{d}{d x} (arcsin (2 x - 1))

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 t}, y (0) = 1, y^{^{'}} (0) = 0

x \to \infty lim (\frac{1}{3})

\frac{d y}{d x} + 2 y - 8 e^{- x} = 0, y (0) = 7

\int_{0}^{1} (e^{x}) - (x e^{x^{2}}) d x

What is area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 ?
The answer to area f(x)= x/(sqrt(9-x^2)),g(y)=0,y=2 is No Solution