What is the derivative of f(t)= 1/t ?

The derivative of f(t)= 1/t is -1/(t^2)

What is the first derivative of f(t)= 1/t ?

The first derivative of f(t)= 1/t is -1/(t^2)

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derivative of

f (t) = \frac{1}{t}

- \frac{1}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot t^{- 1 - 1}

Simplify

- 1 \cdot t^{- 1 - 1} : - \frac{1}{t ^{2}}

= - \frac{1}{t ^{2}}

d er i v a t i v e x^{2} + 5 x

x ln (2 x) y^{^{'}} - y = 0

\frac{d}{d x} (c cos (x) + x^{2} sin (x))

\frac{\partial}{\partial x} (x^{2} e^{3 x y})

\frac{\partial}{\partial x} (\frac{x}{1 + 2 x + 3 y})

What is the derivative of f(t)= 1/t ?
The derivative of f(t)= 1/t is -1/(t^2)
What is the first derivative of f(t)= 1/t ?
The first derivative of f(t)= 1/t is -1/(t^2)