What is the limit as x approaches infinity of e^x-1 ?

The limit as x approaches infinity of e^x-1 is infinity

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limit as x approaches infinity of e^x-1

x \to \infty lim (e^{x} - 1)

\infty

Solution steps

x \to \infty lim (e^{x} - 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (e^{x}) - x \to \infty lim (1)

x \to \infty lim (e^{x}) = \infty

x \to \infty lim (1) = 1

= \infty - 1

Apply Infinity Property:

\infty - c = \infty

= \infty

x \to - 7 lim (\frac{x ^{2} - 4}{7 - x})

\int 6 x e^{- 3 x} d x

d er i v a t i v e \frac{9}{( 9 - x ^{6} ) ^{\frac{3}{2}}}

\int x 9 - x^{2} d x

x \to 0 lim (\frac{x ^{2} - 1}{x})

What is the limit as x approaches infinity of e^x-1 ?
The limit as x approaches infinity of e^x-1 is infinity