(xy^')/(e^y+1)=2

Lösung

\frac{x y ^{^{'}}}{e ^{y} + 1} = 2

y = ln (- \frac{x ^{2}}{x ^{2} - c _{1}})

Schritte zur Lösung

\frac{x y ^{'} ( x )}{e ^{y} + 1} = 2

Solve linear ODE:

y = ln (- \frac{x ^{2}}{x ^{2} - c _{1}})

y = ln (- \frac{x ^{2}}{x ^{2} - c _{1}})

\int_{- 3}^{1} \frac{x}{9 - x ^{2}} d x

\int \frac{e ^{2 x}}{e ^{2 x} + 6} d x

\frac{d}{d x} (- 2 (- 2 e^{- x^{2}} x^{2} + e^{- x^{2}}))

\frac{d}{d x} (r (x) cos^{2} (r (x) x))

t an g e n t f (x) = \frac{2}{x + 1}, at x = 3, y = 1