(d^2)/(dx^2)(3ln(sec(x)+tan(x)))

解答

\frac{d ^{2}}{d x ^{2}} (3 ln (sec (x) + tan (x)))

\frac{3 ( - 1 + cos ( x ) ( sec ( x ) + tan ( x ) ) )}{( sec ( x ) + tan ( x ) ) ^{2} ( - 1 + sin ( x ) ) ^{2}}

求解步骤

\frac{d ^{2}}{d x ^{2}} (3 ln (sec (x) + tan (x)))

\frac{d}{d x} (3 ln (sec (x) + tan (x))) = - \frac{3}{( sec ( x ) + tan ( x ) ) ( - 1 + sin ( x ) )}

= \frac{d}{d x} (- \frac{3}{( sec ( x ) + tan ( x ) ) ( - 1 + sin ( x ) )})

\frac{d}{d x} (- \frac{3}{( sec ( x ) + tan ( x ) ) ( - 1 + sin ( x ) )}) = \frac{3 ( - 1 + cos ( x ) ( sec ( x ) + tan ( x ) ) )}{( sec ( x ) + tan ( x ) ) ^{2} ( - 1 + sin ( x ) ) ^{2}}

= \frac{3 ( - 1 + cos ( x ) ( sec ( x ) + tan ( x ) ) )}{( sec ( x ) + tan ( x ) ) ^{2} ( - 1 + sin ( x ) ) ^{2}}

\int_{- 1}^{1} cos (x) d x

y^{^{''}} + 2 y = e^{x} + x^{3}

\int \frac{e ^{x}}{1 - 4 e ^{2 x}} d x

in v erse l a pl a ce \frac{1.5}{( ( s + 1 ) )}

y^{^{'}} = e^{4 y} sin (5 x)