What is the solution for (dy)/(dx)= 1/x (y^2+y) ?

The solution for (dy)/(dx)= 1/x (y^2+y) is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}

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(dy)/(dx)= 1/x (y^2+y)

\frac{d y}{d x} = \frac{1}{x} (y^{2} + y)

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Solution steps

\frac{d y}{d x} = \frac{1}{x} (y^{2} + y)

Solve separable ODE:

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y = \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

\int y 10 + 4 y - 4 y^{2} d y

\int sec^{2} (x t a) n^{4} x d x

\frac{\partial}{\partial y} (\frac{x}{yz})

\int_{1}^{9} x - 1 d x

x \to 0 + lim (x^{t a n (x^{2})})

What is the solution for (dy)/(dx)= 1/x (y^2+y) ?
The solution for (dy)/(dx)= 1/x (y^2+y) is y=(e^{c_{1}}x)/(1-e^{c_{1)}x}