integral from 1 to 9 of sqrt(x-1)

Lösung

\int_{1}^{9} x - 1 d x

\frac{32 2}{3}

Dezimale

15.08494 \dots

Schritte zur Lösung

\int_{1}^{9} x - 1 d x

Wende U-Substitution an

= \int_{0}^{8} u d u

Wende die Potenzregel an

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{8}

Berechne die Grenzen:

\frac{32 2}{3}

= \frac{32 2}{3}

x \to 0 + lim (x^{t a n (x^{2})})

\frac{\partial}{\partial x} (2 k x^{2} y^{2} - x sin (y))

in v erse l a pl a ce \frac{2 e ^{- 2 s}}{s ^{2} - 4}

d er i v a t i v e e^{t} - t

\int \frac{2}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t