(\partial)/(\partial x)(e^{x^2+y^2+1})

Lösung

\frac{\partial}{\partial x} (e^{x^{2} + y^{2} + 1})

e^{x^{2} + y^{2} + 1} \cdot 2 x

Schritte zur Lösung

\frac{\partial}{\partial x} (e^{x^{2} + y^{2} + 1})

Behandle

y

als Konstante

Wende die Kettenregel an:

e^{x^{2} + y^{2} + 1} \frac{\partial}{\partial x} (x^{2} + y^{2} + 1)

= e^{x^{2} + y^{2} + 1} \frac{\partial}{\partial x} (x^{2} + y^{2} + 1)

\frac{\partial}{\partial x} (x^{2} + y^{2} + 1) = 2 x

= e^{x^{2} + y^{2} + 1} \cdot 2 x

x \to \infty lim (\frac{1}{( 2 x + 1 ) ^{\frac{1}{x}}})

\int e^{x} (sin (x)) d x

in v erse l a pl a ce \frac{2}{s ( s ^{2} + 4 s )}

\int_{6}^{8} \frac{84}{( x - 6 ) ^{3}} d x

\frac{d y}{d x} = 2 y sin (x)