2x^2y^'=piysin(pi/(2x))

解答

2 x^{2} y^{^{'}} = π y sin (\frac{π}{2 x})

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

求解步骤

2 x^{2} y^{'} (x) = π y sin (\frac{π}{2 x})

求解可分离方程:

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

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