derivative of 3-7/(2x^{1/8})

Lösung

\frac{d}{d x} (3 - \frac{7}{2 x ^{\frac{1}{8}}})

\frac{7}{16 x ^{\frac{9}{8}}}

Schritte zur Lösung

\frac{d}{d x} (3 - \frac{7}{2 x ^{\frac{1}{8}}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (\frac{7}{2 x ^{\frac{1}{8}}})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (\frac{7}{2 x ^{\frac{1}{8}}}) = - \frac{7}{16 x ^{\frac{9}{8}}}

= 0 - (- \frac{7}{16 x ^{\frac{9}{8}}})

Vereinfache

= \frac{7}{16 x ^{\frac{9}{8}}}

a re a x^{2} + y^{2} = 4, x^{2} + y^{2} = 4 x

\frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{5})

\int \frac{( x ^{2} + 1 - 2 x ) ^{\frac{1}{5}}}{1 - x} d x

\int \frac{x ^{6}}{1 - x ^{14}} d x

\int 3 cot^{4} (x) d x