What is the derivative of (1+6x^2(x-x^2)) ?

The derivative of (1+6x^2(x-x^2)) is -24x^3+18x^2-2x+1

What is the first derivative of (1+6x^2(x-x^2)) ?

The first derivative of (1+6x^2(x-x^2)) is -24x^3+18x^2-2x+1

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\frac{d}{d x} ((1 + 6 x^{2}) (x - x^{2}))

- 24 x^{3} + 18 x^{2} - 2 x + 1

Solution steps

\frac{d}{d x} ((1 + 6 x^{2}) (x - x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 + 6 x^{2}, g = x - x^{2}

= \frac{d}{d x} (1 + 6 x^{2}) (x - x^{2}) + \frac{d}{d x} (x - x^{2}) (1 + 6 x^{2})

\frac{d}{d x} (1 + 6 x^{2}) = 12 x

\frac{d}{d x} (x - x^{2}) = 1 - 2 x

= 12 x (x - x^{2}) + (1 - 2 x) (1 + 6 x^{2})

Simplify

12 x (x - x^{2}) + (1 - 2 x) (1 + 6 x^{2}) : - 24 x^{3} + 18 x^{2} - 2 x + 1

= - 24 x^{3} + 18 x^{2} - 2 x + 1

in v erse l a pl a ce (s + 1) e^{- s π}

\frac{d y}{d x} = (x^{2})

\int (0) d x

3 y^{^{'}} + 7 y = 4 e^{- x}

\frac{d y}{d x} = - 2 x tan (y)

What is the derivative of (1+6x^2(x-x^2)) ?
The derivative of (1+6x^2(x-x^2)) is -24x^3+18x^2-2x+1
What is the first derivative of (1+6x^2(x-x^2)) ?
The first derivative of (1+6x^2(x-x^2)) is -24x^3+18x^2-2x+1