3y^'+7y=4e^{-x}

Lösung

3 y^{^{'}} + 7 y = 4 e^{- x}

y = \frac{1}{e ^{x}} + \frac{c _{1}}{e ^{\frac{7 x}{3}}}

Schritte zur Lösung

3 y^{'} (x) + 7 y = 4 e^{- x}

Solve linear ODE:

y = \frac{1}{e ^{x}} + \frac{c _{1}}{e ^{\frac{7 x}{3}}}

y = \frac{1}{e ^{x}} + \frac{c _{1}}{e ^{\frac{7 x}{3}}}

\frac{d y}{d x} = - 2 x tan (y)

x \to 8 - lim (x - 8)

t an g e n t f (x) = (e^{2 x} - 4)^{2}, (0, 9)

x \to 0 lim (\frac{2 cos ( x ) - 2}{x})

x \to \infty lim (7^{x})