integral from 5 to 1 of-4x+1

Lösung

\int_{5}^{1} - 4 x + 1 d x

44

Schritte zur Lösung

\int_{5}^{1} - 4 x + 1 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{5} - 4 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (- \int_{1}^{5} 4 x d x + \int_{1}^{5} 1 d x)

\int_{1}^{5} 4 x d x = 48

\int_{1}^{5} 1 d x = 4

= - (- 48 + 4)

Vereinfache

= 44

n = 0 \sum \infty - 2 - 8 - 32 - 128

x \to 3 lim (\frac{x ^{2} + 5}{x + 5})

\frac{d}{d x} (ln (x^{2} - 3 x + 1))

t an g e n t y = x^{2} - 1, (- 3, 8)

\frac{\partial}{\partial x} (6 x - 5 y)