What is the sum from n=0 to infinity of-2-8-32-128 ?

The sum from n=0 to infinity of-2-8-32-128 is diverges

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sum from n=0 to infinity of-2-8-32-128

n = 0 \sum \infty - 2 - 8 - 32 - 128

diverges

Solution steps

n = 0 \sum \infty - 2 - 8 - 32 - 128

Every infinite sum of a non-zero constant diverges

= diverges

x \to 3 lim (\frac{x ^{2} + 5}{x + 5})

\frac{d}{d x} (ln (x^{2} - 3 x + 1))

t an g e n t y = x^{2} - 1, (- 3, 8)

\frac{\partial}{\partial x} (6 x - 5 y)

n = 1 \sum \infty (- 1)^{n} \frac{n}{n + 2}

What is the sum from n=0 to infinity of-2-8-32-128 ?
The sum from n=0 to infinity of-2-8-32-128 is diverges