What is the sum from n=0 to infinity of (-3x)^n ?

The sum from n=0 to infinity of (-3x)^n is Interval of convergence is-1/3 <x< 1/3

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sum from n=0 to infinity of (-3x)^n

n = 0 \sum \infty (- 3 x)^{n}

Interval of convergence is - \frac{1}{3} < x < \frac{1}{3}

Solution steps

n = 0 \sum \infty (- 3 x)^{n}

Use the Root Test to compute the convergence interval

Interval of convergence is - \frac{1}{3} < x < \frac{1}{3}

x \to 0 lim (1 - cos^{2} (x))

\int (4 + t) d t

t an g e n t y = 3 x^{2} + 2 x, (- 1, 1)

\int ln (y^{2} + 1) d y

\frac{d}{d θ} (4 cos (θ))

What is the sum from n=0 to infinity of (-3x)^n ?
The sum from n=0 to infinity of (-3x)^n is Interval of convergence is-1/3 <x< 1/3