What is the derivative of (ln(8x))/(8x) ?

The derivative of (ln(8x))/(8x) is (1-ln(8x))/(8x^2)

What is the first derivative of (ln(8x))/(8x) ?

The first derivative of (ln(8x))/(8x) is (1-ln(8x))/(8x^2)

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derivative of

\frac{ln ( 8 x )}{8 x}

\frac{1 - ln ( 8 x )}{8 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ( 8 x )}{8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (\frac{ln ( 8 x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{8} \cdot \frac{\frac{d}{d x} ( ln ( 8 x ) ) x - \frac{d x}{d x} ln ( 8 x )}{x ^{2}}

\frac{d}{d x} (ln (8 x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{8} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 8 x )}{x ^{2}}

Simplify

\frac{1}{8} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 8 x )}{x ^{2}} : \frac{1 - ln ( 8 x )}{8 x ^{2}}

= \frac{1 - ln ( 8 x )}{8 x ^{2}}

\int \frac{3}{e ^{x}} d x

\frac{d}{d x} (3 x (x^{2} + 4))

\int e^{- v} d v

s l o p e (2, 3), (4, - 4)

t a y l or x \cdot e^{- x + 1}, 1

What is the derivative of (ln(8x))/(8x) ?
The derivative of (ln(8x))/(8x) is (1-ln(8x))/(8x^2)
What is the first derivative of (ln(8x))/(8x) ?
The first derivative of (ln(8x))/(8x) is (1-ln(8x))/(8x^2)