taylor x*ln(x),1

Lösung

taylor

x \cdot ln (x), 1

(x - 1) + \frac{1}{2} (x - 1)^{2} - \frac{1}{6} (x - 1)^{3} + \frac{1}{12} (x - 1)^{4} - \frac{1}{20} (x - 1)^{5} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( x ln ( x ) ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( x ln ( x ) ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ln ( x ) ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 0 + \frac{1}{1 !} (x - 1) + \frac{1}{2 !} (x - 1)^{2} + \frac{- 1}{3 !} (x - 1)^{3} + \frac{2}{4 !} (x - 1)^{4} + \frac{- 6}{5 !} (x - 1)^{5} + \dots

Fasse zusammen

= (x - 1) + \frac{1}{2} (x - 1)^{2} - \frac{1}{6} (x - 1)^{3} + \frac{1}{12} (x - 1)^{4} - \frac{1}{20} (x - 1)^{5} + \dots

\int (- 3 \cdot cos (x) + 4 \cdot sec^{2} (x)) d x

\int \frac{1}{a - b x} d x

d er i v a t i v e y = x^{2} - 1

x y^{^{'}} + y + y ln (x y) = 0

r \to 0 lim (\frac{1}{r ^{2}})