laplacetransform sin(4t)+cos(4t)

Lösung

laplace transformation

sin (4 t) + cos (4 t)

\frac{4}{s ^{2} + 16} + \frac{s}{s ^{2} + 16}

Schritte zur Lösung

L {sin (4 t) + cos (4 t)}

Verwende die lineare Eigenschaft der Laplace-Transformation:

Für Funktionen

f (t), g (t)

und Konstanten

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {sin (4 t)} + L {cos (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

L {cos (4 t)} : \frac{s}{s ^{2} + 16}

= \frac{4}{s ^{2} + 16} + \frac{s}{s ^{2} + 16}

in v erse l a pl a ce \frac{1}{s ( s + 1 ) ^{4}}

\int 3 tan (5 x) sec^{2} (5 x) d x

h \to 0 lim (5 x^{2} + 8 y^{2})

n = 0 \sum \infty (2 n)! (\frac{x}{3})^{n}

in v erse l a pl a ce \frac{1}{( 5 s ^{2} + s )}