(dy)/(dx)=1

Lösung

\frac{d y}{d x} = 1

y = x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = 1

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = 1

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 1 d x

\int 1 d x = x + c_{1}

y = x + c_{1}

\int \frac{( x + 1 ) ^{4}}{2 x} d x

\frac{d}{d x} (x^{2} sin (4 x - 3))

x \to - 2 lim (\frac{3 x + 6}{x + 2})

\int (1 + e)^{5} d x

\int_{1}^{16} \frac{1}{3 - x} d x