integral from 1 to 16 of 1/(3-sqrt(x))

解答

\int_{1}^{16} \frac{1}{3 - x} d x

发散

求解步骤

\int_{1}^{16} \frac{1}{3 - x} d x

找到无定义的点（奇点）:

x = 9

如果存在

b, a < b < c, f (b) =

无定义

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{1}^{9} \frac{1}{3 - x} d x + \int_{9}^{16} \frac{1}{3 - x} d x

\int_{1}^{9} \frac{1}{3 - x} d x =

发散

如果表达式有部分发散，则整个表达式发散

= 发散

4 t \cdot \frac{d y}{d t} - y = t

x \to 0 lim (tan (5 x))

x \to 1 - lim (3 x - 1)

a re a y = x^{2} - x^{3}, (0, 1)

\frac{\partial}{\partial x} (sec^{2} (x))