What is the derivative of 1/(2x^3) ?

The derivative of 1/(2x^3) is -3/(2x^4)

What is the first derivative of 1/(2x^3) ?

The first derivative of 1/(2x^3) is -3/(2x^4)

\frac{d}{d x} (\frac{1}{2 x ^{3}})

- \frac{3}{2 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 3 x^{- 3 - 1})

Simplify

\frac{1}{2} (- 3 x^{- 3 - 1}) : - \frac{3}{2 x ^{4}}

= - \frac{3}{2 x ^{4}}

\frac{\partial}{\partial r} (r e^{s})

\int \frac{4 x ^{3} - x ^{2} + 4 x + 2}{( x ^{2} + 1 ) ^{2}} d x

x \to 6 - lim (\frac{1}{( x - 6 ) ^{2}})

x \to 1 lim (2 x + 4)

d er i v a t i v e e^{- 2 x^{2}}

What is the derivative of 1/(2x^3) ?
The derivative of 1/(2x^3) is -3/(2x^4)
What is the first derivative of 1/(2x^3) ?
The first derivative of 1/(2x^3) is -3/(2x^4)