What is the derivative of f(x)=x-4 ?

The derivative of f(x)=x-4 is 1

What is the first derivative of f(x)=x-4 ?

The first derivative of f(x)=x-4 is 1

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derivative of

f (x) = x - 4

1

Solution steps

\frac{d}{d x} (x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (4)

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (\frac{1}{2 x ^{3}})

\frac{\partial}{\partial r} (r e^{s})

\int \frac{4 x ^{3} - x ^{2} + 4 x + 2}{( x ^{2} + 1 ) ^{2}} d x

x \to 6 - lim (\frac{1}{( x - 6 ) ^{2}})

x \to 1 lim (2 x + 4)

What is the derivative of f(x)=x-4 ?
The derivative of f(x)=x-4 is 1
What is the first derivative of f(x)=x-4 ?
The first derivative of f(x)=x-4 is 1