What is the derivative of 2e^{3x}-2x-2 ?

The derivative of 2e^{3x}-2x-2 is 6e^{3x}-2

What is the first derivative of 2e^{3x}-2x-2 ?

The first derivative of 2e^{3x}-2x-2 is 6e^{3x}-2

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\frac{d}{d x} (2 e^{3 x} - 2 x - 2)

6 e^{3 x} - 2

Solution steps

\frac{d}{d x} (2 e^{3 x} - 2 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{3 x}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 e^{3 x}) = 6 e^{3 x}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= 6 e^{3 x} - 2 - 0

Simplify

= 6 e^{3 x} - 2

\int_{1}^{2} (x^{2} - 5 x + 3) d x

\int \frac{5}{x 4 - ln ^{2} ( x )} d x

\frac{d}{d x} (- 12 x cos (x^{2}) + 8 x^{3} sin (x^{2}))

in v erse l a pl a ce \frac{1}{s ^{2} + 6 s + 13}

d er i v a t i v e f (x) = x - 4

What is the derivative of 2e^{3x}-2x-2 ?
The derivative of 2e^{3x}-2x-2 is 6e^{3x}-2
What is the first derivative of 2e^{3x}-2x-2 ?
The first derivative of 2e^{3x}-2x-2 is 6e^{3x}-2