What is the derivative of tan(x^2+1) ?

The derivative of tan(x^2+1) is sec^2(x^2+1)*2x

What is the first derivative of tan(x^2+1) ?

The first derivative of tan(x^2+1) is sec^2(x^2+1)*2x

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\frac{d}{d x} (tan (x^{2} + 1))

sec^{2} (x^{2} + 1) \cdot 2 x

Solution steps

\frac{d}{d x} (tan (x^{2} + 1))

Apply the chain rule:

sec^{2} (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

= sec^{2} (x^{2} + 1) \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= sec^{2} (x^{2} + 1) \cdot 2 x

7

y^{^{'}} + a y + b = 0

(\frac{2 - 2 x}{2 x - x ^{2} + 3})^{^{'}}

\int \frac{1}{( z ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{100}{x ^{2}} d x

What is the derivative of tan(x^2+1) ?
The derivative of tan(x^2+1) is sec^2(x^2+1)*2x
What is the first derivative of tan(x^2+1) ?
The first derivative of tan(x^2+1) is sec^2(x^2+1)*2x