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Popular >

y^'+ay+b=0

Solution

y^{^{'}} + a y + b = 0

Solution

y = \frac{e ^{- t a - c_{1} a}}{a} - \frac{b}{a}

Solution steps

y^{'} (t) + a y (t) + b = 0

Solve separable ODE:

y = \frac{e ^{- t a - c_{1} a}}{a} - \frac{b}{a}

y = \frac{e ^{- t a - c_{1} a}}{a} - \frac{b}{a}

Popular Examples

((2-2x)/(2x-x^2+3))^'

(\frac{2 - 2 x}{2 x - x ^{2} + 3})^{^{'}}

integral of 1/((z^2+x^2)^{3/2)}

\int \frac{1}{( z ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x

integral of (100)/(x^2)

\int \frac{100}{x ^{2}} d x

derivative of x^2+3x+14 derivative of

x^{2} + 3 x + 14

integral of x/(sqrt(8+x^2))

\int \frac{x}{8 + x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+ay+b=0 ?
The solution for y^'+ay+b=0 is y=(e^{-ta-c_{1}a})/a-b/a