What is the limit as x approaches 0+of ln^2(x) ?

The limit as x approaches 0+of ln^2(x) is infinity

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limit as x approaches 0+of ln^2(x)

x \to 0 + lim (ln^{2} (x))

\infty

Solution steps

x \to 0 + lim (ln^{2} (x))

x \to a lim [f (x)]^{b} = [x \to a lim f (x)]^{b}

With the exception of indeterminate form

= (x \to 0 + lim (ln (x)))^{2}

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= (- \infty)^{2}

Apply Infinity Property:

(- \infty)^{n} = \infty, n

is even

= \infty

x \to 2 lim (\frac{x + 6}{x ^{2}})

x \to 0.9 lim (x^{2} + 3 x + 2)

d er i v a t i v e f (x) = e^{- 2.5 x^{2}}

n = 1 \sum \infty (- 1)^{n - 1} (\frac{7}{9 ^{n} - 1})

\frac{d}{d x} (\frac{x ^{4} + 9}{x ^{2}})

What is the limit as x approaches 0+of ln^2(x) ?
The limit as x approaches 0+of ln^2(x) is infinity