(\partial)/(\partial x)(1.015sqrt(E(m,x)bh^3m^{-1)L^{-4}})

解答

\frac{\partial}{\partial x} (1.015 E (m, x) b h^{3} m^{- 1} L^{- 4})

1.015 \cdot \frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} b h^{3} m^{- 1} L^{- 4} \frac{\partial}{\partial x} (E (m, x))

求解步骤

\frac{\partial}{\partial x} (1.015 E (m, x) b h^{3} m^{- 1} L^{- 4})

将

b, h, L, m

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 1.015 \frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4})

使用连锁律:

\frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} \frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4})

= \frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} \frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4})

\frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4}) = b h^{3} m^{- 1} L^{- 4} \frac{\partial}{\partial x} (E (m, x))

= 1.015 \cdot \frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} b h^{3} m^{- 1} L^{- 4} \frac{\partial}{\partial x} (E (m, x))

\frac{d}{d x} (cot^{4} (x) - csc^{4} (x))

d er i v a t i v e y = 2^{2 x}

d er i v a t i v e y = e^{in (x^{2} + 1)}

x \to 2 lim (\frac{3 3 x ^{2} - 2 x - 8}{( x + 2 ) ^{3}})

t a y l or \frac{1}{( 1 + x ^{2} )}