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Beliebt Rechnen >

(\partial)/(\partial x)(1.015sqrt(E(m,x)bh^3m^{-1)L^{-4}})

Lösung

\frac{\partial}{\partial x} (1.015 E (m, x) b h^{3} m^{- 1} L^{- 4})

Lösung

1.015 \cdot \frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} b h^{3} m^{- 1} L^{- 4} \frac{\partial}{\partial x} (E (m, x))

Schritte zur Lösung

\frac{\partial}{\partial x} (1.015 E (m, x) b h^{3} m^{- 1} L^{- 4})

Behandle

b, h, L, m

als Konstante

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 1.015 \frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4})

Wende die Kettenregel an:

\frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} \frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4})

= \frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} \frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4})

\frac{\partial}{\partial x} (E (m, x) b h^{3} m^{- 1} L^{- 4}) = b h^{3} m^{- 1} L^{- 4} \frac{\partial}{\partial x} (E (m, x))

= 1.015 \cdot \frac{1}{2 E ( m , x ) b h ^{3} m ^{- 1} L ^{- 4}} b h^{3} m^{- 1} L^{- 4} \frac{\partial}{\partial x} (E (m, x))

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