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Beliebt Rechnen >

inverselaplace 2/((s-1)^2)

Lösung

inverse laplace transformation

\frac{2}{( s - 1 ) ^{2}}

Lösung

e^{t} \cdot 2 t

Schritte zur Lösung

L^{- 1} {\frac{2}{( s - 1 ) ^{2}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{2}{( s - 1 ) ^{2}} : a = 1, F (s) = \frac{2}{s ^{2}}

= e^{t} L^{- 1} {\frac{2}{s ^{2}}}

L^{- 1} {\frac{2}{s ^{2}}} : 2 t

= e^{t} \cdot 2 t

Beliebte Beispiele

integral of (9x)/(3x+1)

\int \frac{9 x}{3 x + 1} d x

tangent f(x)=(sqrt(x))/(x+3),\at x=4

t an g e n t f (x) = \frac{x}{x + 3}, at x = 4

inverselaplace 1/(s(s-2)^2)

in v erse l a pl a ce \frac{1}{s ( s - 2 ) ^{2}}

tangent y= x/(sqrt(64+x^2)),(0,0)

t an g e n t y = \frac{x}{64 + x ^{2}}, (0, 0)

derivative of 2sin(x-1)

\frac{d}{d x} (2 sin (x) - 1)