What is the integral of (2/(x^2)) ?

The integral of (2/(x^2)) is -2/x+C

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integral of (2/(x^2))

\int (\frac{2}{x ^{2}}) d x

- \frac{2}{x} + C

Solution steps

\int \frac{2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= 2 (- \frac{1}{x})

Simplify

2 (- \frac{1}{x}) : - \frac{2}{x}

= - \frac{2}{x}

Add a constant to the solution

= - \frac{2}{x} + C

\frac{\partial}{\partial x} (\frac{1}{x} - \frac{y}{x})

\int tan^{2} (x) tan (x) d x

\int \frac{7}{( x - 3 ) x ^{2} - 6 x + 5} d x

\frac{\partial}{\partial x} (e^{- x} sin (x))

\frac{d}{d x} (\frac{8}{x - 5})