taylor x^2e^{x-1},\at 1

Lösung

taylor

x^{2} e^{x - 1}, at 1

\frac{2 at 1 \cdot e ^{at 1 - 1} + e ^{at 1 - 1} ( at 1 ) ^{2}}{1 !} (x - at 1) + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 4 e ^{at 1 - 1} at 1 + 2 e ^{at 1 - 1}}{2 !} (x - at 1)^{2} + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 6 e ^{at 1 - 1} at 1 + 6 e ^{at 1 - 1}}{3 !} (x - at 1)^{3} + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 8 e ^{at 1 - 1} at 1 + 12 e ^{at 1 - 1}}{4 !} (x - at 1)^{4} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= (at 1)^{2} e^{at 1 - 1} + \frac{\frac{d}{d x} ( x ^{2} e ^{x - 1} ) ( at 1 )}{1 !} (x - at 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{2} e ^{x - 1} ) ( at 1 )}{2 !} (x - at 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{2} e ^{x - 1} ) ( at 1 )}{3 !} (x - at 1)^{3} + \dots

Evaluate Derivatives

= (at 1)^{2} e^{at 1 - 1} + \frac{2 at 1 \cdot e ^{at 1 - 1} + e ^{at 1 - 1} ( at 1 ) ^{2}}{1 !} (x - at 1) + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 4 e ^{at 1 - 1} at 1 + 2 e ^{at 1 - 1}}{2 !} (x - at 1)^{2} + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 6 e ^{at 1 - 1} at 1 + 6 e ^{at 1 - 1}}{3 !} (x - at 1)^{3} + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 8 e ^{at 1 - 1} at 1 + 12 e ^{at 1 - 1}}{4 !} (x - at 1)^{4} + \dots

Fasse zusammen

= \frac{2 at 1 \cdot e ^{at 1 - 1} + e ^{at 1 - 1} ( at 1 ) ^{2}}{1 !} (x - at 1) + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 4 e ^{at 1 - 1} at 1 + 2 e ^{at 1 - 1}}{2 !} (x - at 1)^{2} + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 6 e ^{at 1 - 1} at 1 + 6 e ^{at 1 - 1}}{3 !} (x - at 1)^{3} + \frac{e ^{at 1 - 1} ( at 1 ) ^{2} + 8 e ^{at 1 - 1} at 1 + 12 e ^{at 1 - 1}}{4 !} (x - at 1)^{4} + \dots

\int cot (19 x) d x

\int x^{2} (3 x^{3} - 2)^{4} d x

\frac{d}{d x} (k^{x} + x^{k})

\int_{0}^{2} 2 π (x + 1) (12 - 6 x) d x

d er i v a t i v e g (x) = 3^{(\frac{x}{2})}