derivative of k^x+x^k

Lösung

\frac{d}{d x} (k^{x} + x^{k})

k^{x} ln (k) + k x^{k - 1}

Schritte zur Lösung

\frac{d}{d x} (k^{x} + x^{k})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (k^{x}) + \frac{d}{d x} (x^{k})

\frac{d}{d x} (k^{x}) = k^{x} ln (k)

\frac{d}{d x} (x^{k}) = k x^{k - 1}

= k^{x} ln (k) + k x^{k - 1}

\int_{0}^{2} 2 π (x + 1) (12 - 6 x) d x

d er i v a t i v e g (x) = 3^{(\frac{x}{2})}

x \to 2 lim (\frac{( 3 )}{x - 2})

\int sec^{7} (3 x) tan (3 x) d x

x \to 0 - lim (cot (x))