What is the derivative of (2x^2)/5 ?

The derivative of (2x^2)/5 is (4x)/5

What is the first derivative of (2x^2)/5 ?

The first derivative of (2x^2)/5 is (4x)/5

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derivative of

\frac{2 x ^{2}}{5}

\frac{4 x}{5}

Solution steps

\frac{d}{d x} (\frac{2 x ^{2}}{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{5} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{5} \cdot 2 x^{2 - 1}

Simplify

\frac{2}{5} \cdot 2 x^{2 - 1} : \frac{4 x}{5}

= \frac{4 x}{5}

x \to 0 lim (\frac{a ^{x} - 1}{x})

\int 2 x (x^{2} + 4)^{3} d x

\frac{d}{d x} ((x - 1)^{- 1})

\int \frac{1}{e ^{x} 1 - e ^{2 x}} d x

f (x) = sin^{2} (\frac{x}{2})

What is the derivative of (2x^2)/5 ?
The derivative of (2x^2)/5 is (4x)/5
What is the first derivative of (2x^2)/5 ?
The first derivative of (2x^2)/5 is (4x)/5