What is the tangent of y=e^{4x},\at x= 1/4 ln(5) ?

The tangent of y=e^{4x},\at x= 1/4 ln(5) is y=20x+5-5ln(5)

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tangent of y=e^{4x},\at x= 1/4 ln(5)

tangent of

y = e^{4 x}, at x = \frac{1}{4} ln (5)

y = 20 x + 5 - 5 ln (5)

Solution steps

Find the tangent point:

(\frac{1}{4} ln (5), 5)

Find the slope of

y = e^{4 x} : \frac{d y}{d x} = e^{4 x} \cdot 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 20

Find the line with slope m=

20

and passing through

(\frac{1}{4} ln (5), 5) : y = 20 x + 5 - 5 ln (5)

y = 20 x + 5 - 5 ln (5)

\frac{d}{d x} ((4 + 8 x) cosh (2 x))

5 \cdot sin (2 \cdot t)

\frac{d}{d x} (x y e^{x})

\frac{d}{d x} (\frac{x ^{2} + 2 x - 5}{( x + 1 ) ^{2}})

y^{^{''}} + \frac{9}{t} y^{^{'}} + \frac{15}{t ^{2}} y = 0

What is the tangent of y=e^{4x},\at x= 1/4 ln(5) ?
The tangent of y=e^{4x},\at x= 1/4 ln(5) is y=20x+5-5ln(5)