What is the solution for (dy)/(dt)=e^{-2t+3y} ?

The solution for (dy)/(dt)=e^{-2t+3y} is y=-(ln(3/2 e^{-2t}-c_{1}))/3

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(dy)/(dt)=e^{-2t+3y}

\frac{d y}{d t} = e^{- 2 t + 3 y}

y = - \frac{ln ( \frac{3}{2} e ^{- 2 t} - c _{1} )}{3}

Solution steps

\frac{d y}{d t} = e^{- 2 t + 3 y}

Solve separable ODE:

y = - \frac{ln ( \frac{3}{2} e ^{- 2 t} - c _{1} )}{3}

y = - \frac{ln ( \frac{3}{2} e ^{- 2 t} - c _{1} )}{3}

(- 2, - 6), (1, 6)

\int x y - y^{2} d x

\frac{d y}{d x} = 0.2 y - 0.001 y^{2}

y = ln (4 t)

y = 2 x^{2} - x^{4}, (1, 1)

What is the solution for (dy)/(dt)=e^{-2t+3y} ?
The solution for (dy)/(dt)=e^{-2t+3y} is y=-(ln(3/2 e^{-2t}-c_{1}))/3