What is (\partial)/(\partial x)(x-2y+2z) ?

The answer to (\partial)/(\partial x)(x-2y+2z) is 1

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(\partial)/(\partial x)(x-2y+2z)

\frac{\partial}{\partial x} (x - 2 y + 2 z)

1

Solution steps

\frac{\partial}{\partial x} (x - 2 y + 2 z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (2 z)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (2 z) = 0

= 1 - 0 + 0

Simplify

= 1

t an g e n t y = - 3 x^{2} + 2

x \to 0 lim (\frac{5 x}{tan ( x )})

\int 2 + tan^{2} (θ) d θ

\frac{d}{d x} (\frac{x ^{3}}{7})

\frac{\partial}{\partial x} (x y^{2} e^{- x z})

What is (\partial)/(\partial x)(x-2y+2z) ?
The answer to (\partial)/(\partial x)(x-2y+2z) is 1