What is the derivative of (x^3/7) ?

The derivative of (x^3/7) is (3x^2)/7

What is the first derivative of (x^3/7) ?

The first derivative of (x^3/7) is (3x^2)/7

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\frac{d}{d x} (\frac{x ^{3}}{7})

\frac{3 x ^{2}}{7}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{7} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{7} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{7} \cdot 3 x^{3 - 1} : \frac{3 x ^{2}}{7}

= \frac{3 x ^{2}}{7}

\frac{\partial}{\partial x} (x y^{2} e^{- x z})

t a y l or arcsin (x)

y^{^{'}} + y = 5 cos (2 t), y (0) = 3

\frac{d}{d x} (\frac{x - 3}{x ^{2} + 4 x + 4})

\int \frac{1}{1 - x ^{2} - 4 x} d x

What is the derivative of (x^3/7) ?
The derivative of (x^3/7) is (3x^2)/7
What is the first derivative of (x^3/7) ?
The first derivative of (x^3/7) is (3x^2)/7