integral from 0 to 1 of integral of 1

Lösung

\int_{0}^{1} \int 1 d x d y

x + C

Schritte zur Lösung

\int_{0}^{1} \int 1 d x d y

\int 1 d x = x + C

= \int_{0}^{1} (x + C) d y

\int_{0}^{1} (x + C) d y = x + C

= x + C

x \to 4 lim (x + 2)

\int_{1}^{8} π (x - 1) d x

t an g e n t f (x) = 3 x^{2} + 8 x + 4, at x = - 1

x \to 0 lim (x^{3} + 2 x^{2} - x - 2)

x \to 0 - lim (\frac{x + ∣ x ∣}{x})