en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

integral from 0 to 1 of integral of 1

Solution

\int_{0}^{1} \int 1 d x d y

Solution

x + C

Solution steps

\int_{0}^{1} \int 1 d x d y

\int 1 d x = x + C

= \int_{0}^{1} (x + C) d y

\int_{0}^{1} (x + C) d y = x + C

= x + C

Popular Examples

limit as x approaches 4 of sqrt(x+2)

integral from 1 to 8 of pi(x-1)

tangent of f(x)=3x^2+8x+4,\at x=-1

limit as x approaches 0 of x^3+2x^2-x-2

limit as x approaches 0-of (x+|x|)/x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of integral of 1 ?
The integral from 0 to 1 of integral of 1 is x+C