What is the derivative of acos(x+bsin(x)) ?

The derivative of acos(x+bsin(x)) is -asin(x)+bcos(x)

What is the first derivative of acos(x+bsin(x)) ?

The first derivative of acos(x+bsin(x)) is -asin(x)+bcos(x)

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\frac{d}{d x} (a cos (x) + b sin (x))

- a sin (x) + b cos (x)

Solution steps

\frac{d}{d x} (a cos (x) + b sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (x)) + \frac{d}{d x} (b sin (x))

\frac{d}{d x} (a cos (x)) = - a sin (x)

\frac{d}{d x} (b sin (x)) = b cos (x)

= - a sin (x) + b cos (x)

\int 16 - x^{2} d x

a re a y = x^{3}, y = 0, x = 1, x = 2

\int_{0}^{\frac{19}{6}} π (\frac{19}{6} - x)^{2} d x

t an g e n t f (x) = e^{8 x} cos (π x), at x = 0

\frac{\partial}{\partial z} (r cos (t))

What is the derivative of acos(x+bsin(x)) ?
The derivative of acos(x+bsin(x)) is -asin(x)+bcos(x)
What is the first derivative of acos(x+bsin(x)) ?
The first derivative of acos(x+bsin(x)) is -asin(x)+bcos(x)