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受欢迎的微积分 >

tangent f(x)=e^{8x}cos(pix),\at x=0

解答

切线

f (x) = e^{8 x} cos (π x), at x = 0

解答

y = 8 x + 1

求解步骤

找到切点:

(0, 1)

计算

f (x) = e^{8 x} cos (π x)

的斜率:

\frac{df ( x )}{d x} = 8 e^{8 x} cos (π x) - π e^{8 x} sin (π x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

找到斜率 m=

8

且穿过

(0, 1)

的直线:

y = 8 x + 1

y = 8 x + 1

作图

流行的例子

(\partial)/(\partial z)(rcos(t))

\frac{\partial}{\partial z} (r cos (t))

laplacetransform 1-2e^{-2t}

l a pl a ce t r an s f or m 1 - 2 e^{- 2 t}

limit as x approaches 3 of 2x^2+4x+1

x \to 3 lim (2 x^{2} + 4 x + 1)

y^{''}-2y^'+5y=25x^2+12

y^{^{''}} - 2 y^{^{'}} + 5 y = 25 x^{2} + 12

integral from 0 to 2 of (3t)/((3-t)^2)

\int_{0}^{2} \frac{3 t}{( 3 - t ) ^{2}} d t