What is area f(x)=x^4-4x^2,g(x)=x^2-4 ?

The answer to area f(x)=x^4-4x^2,g(x)=x^2-4 is 8

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area f(x)=x^4-4x^2,g(x)=x^2-4

area

f (x) = x^{4} - 4 x^{2}, g (x) = x^{2} - 4

8

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{4} - 4 x^{2} - (x^{2} - 4) d x

Solve

\int_{- 2}^{2} x^{4} - 4 x^{2} - (x^{2} - 4) d x : 8

The area is:

= 8

\int (6 x + 2) d x

\frac{d}{d x} (e - x)

d er i v a t i v e - \frac{8}{x ^{3}}

\frac{d}{d L} ((2 L + K (L))^{\frac{1}{3}})

x \to 0 lim (x^{2} cos^{2} (2 x))

What is area f(x)=x^4-4x^2,g(x)=x^2-4 ?
The answer to area f(x)=x^4-4x^2,g(x)=x^2-4 is 8