What is (\partial)/(\partial x)(e^x-e^{x^2}) ?

The answer to (\partial)/(\partial x)(e^x-e^{x^2}) is e^x-e^{x^2}*2x

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(\partial)/(\partial x)(e^x-e^{x^2})

\frac{\partial}{\partial x} (e^{x} - e^{x^{2}})

e^{x} - e^{x^{2}} \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (e^{x} - e^{x^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) - \frac{\partial}{\partial x} (e^{x^{2}})

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= e^{x} - e^{x^{2}} \cdot 2 x

\int tan (2 x) sec (2 x) d x

\frac{\partial}{\partial x} (600 - 4 x + 10 x^{2} y)

f (x) = \frac{x ^{2} - 5 x + 4}{x ^{2} + 5 x + 4}

y = x + 5, (4, 3)

\int (- \frac{2000}{x ^{2}}) d x

What is (\partial)/(\partial x)(e^x-e^{x^2}) ?
The answer to (\partial)/(\partial x)(e^x-e^{x^2}) is e^x-e^{x^2}*2x