What is the integral of (-(2000)/(x^2)) ?

The integral of (-(2000)/(x^2)) is (2000)/x+C

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integral of (-(2000)/(x^2))

\int (- \frac{2000}{x ^{2}}) d x

\frac{2000}{x} + C

Solution steps

\int - \frac{2000}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2000 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

= - 2000 (- \frac{1}{x})

Simplify

- 2000 (- \frac{1}{x}) : \frac{2000}{x}

= \frac{2000}{x}

Add a constant to the solution

= \frac{2000}{x} + C

\frac{d}{d x} (ln (h (x^{2})))

\int t sin (7 t) d t

\int \frac{2 - x}{x ^{2} + 2 x - 3} d x

\int x 3 x + 2 d x

x d x + y e^{- x} d y = 0, y^{0} = 1

What is the integral of (-(2000)/(x^2)) ?
The integral of (-(2000)/(x^2)) is (2000)/x+C